Tom Ayalon

Ch2

1A) range is from 000.000(0) to 111.111(7.875)
1B) the precision .001

2A) (47)10 -> 2  
	47/2 = 23	1
	23/2 = 11	1
	11/2 = 5	1		00101111
	5/2 = 2		1
	2/2 = 1		0
	1/2 = 0		1


2B) (-27)10 ->2
	27/2 = 13	1
	13/2 = 6	1		10011011
	6/2 = 3		0
	3/2 = 1		1
	1/2 = 0		1


2C) (213) 16 -> 10
	3*16^0 = 3
	1*16^1 = 16			531
	2* 16^2 = 512


2D) (10110.101)2 -> 10
	(10110)			(.101)
	0*2^0 = 0		1*2^-1 = .5
	1X2^1 = 2		0*2^-2 = 0
	1*2^2 = 4		1*2^-3 = .125	    22.625
	0*2^3 = 0		   .625
	1*2^4 = 16
	    22				

2E) (34.625) 10→ 4

3A) (011011)2 → 10
1*2^0		1
1*2^1		2
0*2^2		0
1*2^3		8		27
1*2^4		16
0*2^5		0

3B) (-27)10 → 32
32 – 27 = 5
		00000101

3C) (00011011)2 ->16
0001 = 1		1B
1011 = 11

3D) (55.875)10 → unsigned binary

55/2  27  1		.875 X 2 = 1.75
27/2  13  1		.75 X 2 = 1.5
13/2  6    1		.5 X 2 = 1.0
6/2    3    0				110111.111
3/2    1    1
1/2    0    1     

3E) (132.2)4  ->16

132/4	  33   0	0101 = 10
33/4     8     1
8/4	  2     0	    A
2/4       0     1

7) 1000
	0111
           1
	1000
		8

8) 1111
	0000 = 0

9) Two's complement because it can go from 0 to 256.

10)
5-bits signed binary; Largest number:127 / Most negative most:-127 / No. of different number:255
5-bit excess 16; Largest number:127 / Most negative most:-128 / No. of different number:256